you inherit $10,000 with the stipulation that you for the first year the money must be invested in two stocks paying 6% and 11% annual interest respectively. How much should be invested?

At 6% $3,529.412 will be invested

At 11% $6,470.588 will be invested

Explanation:

Let x be the investment for 6% stock

And (10,000-x) is the investment it 11% stock

Let I be interest earned on both investments.

Using the formula

Principal (p) = Interest (I) * Rate (r) * Time (t)

p/RT = I

So considering both investments

x / (6%*1) = (10,000-x) / (11%*1)

x/0.06 = (10,000-x) / 0.11

Cross-multiply

0.11x = 0.06 (10,000-x)

0.11x = 600 - 0.06x

Rearranging

0.11x + 0.06x = 600

0.17x = 600

x = 600/0.17 = 3,529.412 amount invested at 6%

Amount invested at 11% = 10,000-3,529.412

= 6,470.588