A consumer organization estimates that over a 1-year period 19 % of cars will need to be repaired once, 7 % will need repairs twice, and 2 % will require three or more repairs. What is the probability that a car chosen at random will need a) no repairs? b) no more than one repair? c) some repairs?

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9 March, 03:26

A consumer organization estimates that over a 1-year period 19 % of cars will need to be repaired once, 7 % will need repairs twice, and 2 % will require three or more repairs. What is the probability that a car chosen at random will need a) no repairs? b) no more than one repair? c) some repairs?

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Answers (1)

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Friendo · Answer 1

The answer are:

A) 72%

B) 91%

C) 9%

Explanation:

The total amount of cars that will need some type of repair is 28%; 19% will need to be repaired once + 7% will need to be repaired twice + 2% will need to be repaired more than two times.

The amount of cars that wouldn't need any type of repairs is the total amount of cars minus the percentage that need some type of repair; 100% - 28% = 72%.

The amount of cars that will need no repairs or only one repair is the total amount of cars minus the percentage that need more than one of repair; 100% - (7% + 2%) = 91%.

The amount of cars that need some repairs is the sum of those cars that need two repairs plus those that need three or more repairs; 7% + 2% = 9%