Ask Question
16 May, 22:31

Munson Performance Auto, Inc., modifies 375 autos per year. The manager, Adam Munson, is interested in obtaining a measure of overall performance. He has asked you to provide him with a multifactor measure of last year's performance as a benchmark for future comparison. You have assembled the following data. Resource inputs were: labor, 10500 hours; 500 suspension and engine modification kits; and energy, 100000 kilowatt-hours. Average labor cost last year was $25 per hour, kits cost $1,000 each, and energy costs were $5 per kilowatt-hour. The overall performance at Munson Performance Auto, Inc. = autos/dollar of input (round your response to six decimal places).

+4
Answers (1)
  1. 16 May, 23:47
    0
    overall performance 0.000297

    Explanation:

    cost of inputs:

    labor 10,500 hours x 25 each = 262,500

    suspension and engine 500 kits x 1,000 each = 500,000

    energy 100,000 kilowatt-hous x 5 each = 500,000

    total input resource cost 1,262,500

    performance:

    375 / 1,262,500 = 0.00029703

    rounding to 6 decimal places: 0.000297
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Munson Performance Auto, Inc., modifies 375 autos per year. The manager, Adam Munson, is interested in obtaining a measure of overall ...” in 📘 Business if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers