In the sports center, the capacity of swimming pool A is 60 percent of the capacity of swimming pool B. How many more gallons of water are in pool A than in pool B? Pool A is 80 percent full; pool B is 40 percent full. When full, pool B contains 40,000 gallons of water.

Pool A has 3,200 gallons more water than Pool B.

Explanation:

given,

pool B contains water = 40,000 gallons

Capacity of pool A = 60% of Pool B

= 0.6 * 40000

= 24,000 gallons

Pool A has water = 80% of full

= 0.8 * 24,000

= 19,200 gallons

Pool B has water = 40% of full

= 0.4 * 40,000

= 16,000 gallons

Pool A has more water by = 19,200 gallons - 16,000 gallons

= 3,200 gallons

Pool A has 3,200 gallons more water than Pool B.