You have $19,000 to invest, part at 6% and the rest at 7%. If x is the amount invested at 6 %6% , write an algebraic expression that represents the total annual income from both investments. Simplify the expression.

total annual income = 1330 - 0.01x

Explanation:

given data

invest = $19,000

some part at = 6%

remaining part = 7%

x is amount invested at = 6 %

solution

we know x part invested = 6 %

so ($19,000 - x) part invested = 7 %

so we get here total annual income from both investment that is

income = 6% x + (19000 - x) 7%

so total annual income = 0.06x + (19000 - x) 0.07

total annual income = 1330 - 0.01x