Customers exiting a bottleneck form a Poisson process with a stationary flow of 400 per hour. What is the expected amount of time needed to observe one customer's (exit) headway that is larger than five times the mean headway

Customer's (exit) = 0.03 minutes per person

Explanation:

Given:

Flow (Ф) = 400 per hour

Times = 5 times headway

Computation:

5 times Poisson Distribution = 400 per hour * 5 time

5 times Poisson Distribution = 2,000 persons

Computation of expected amount of time needed to observe one customer:

Customer's (exit) = 1 hour / 2,000 persons

Customer's (exit) = 60 minutes / 2,000 persons

Customer's (exit) = 0.03 minutes per person