Ask Question
16 November, 11:32

We conduct a simulation to mimic randomly sampling from a population with of college graduates. In the population 62% had student loans. Each sample has 50 graduates in it. What will be the mean of the distribution of sample proportions? Enter a number in decimal form. For example, you would enter 0.50, not 50 or 50%.

+1
Answers (2)
  1. 16 November, 11:54
    0
    mean is 0.62

    Explanation:

    In statistics, for repeated samples (each with same n), all taken from the same population, when the proportion of interest equals p, then the mean of all p^ should be equal to the population proportion = p.

    In this case, all the samples where taken from college graduates and they all have n = 50, then the mean of the distribution of sample proportions will be equal to the population proportion = 62% = 0.62.
  2. 16 November, 15:12
    0
    The correct answer is 0.069

    Explanation:

    Solution

    Let recall that,

    In the population, the number of student that took loans where = 62%

    Each samples has graduates of = 50

    The next step is to enter a number in decimal form.

    Given that,

    p = 62% = 0.62

    1 - p = 1 - 0.62 = 0.38

    Thus,

    n = 50

    The mean = μ p = p = 0.62

    Then,

    The standard deviation = б p = √{p (1 - p) / n]

    = √[ (0.62 * 0.38) / 50 ] = 0.069

    Therefore, the number form is 0.069
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “We conduct a simulation to mimic randomly sampling from a population with of college graduates. In the population 62% had student loans. ...” in 📘 Business if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers