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6 January, 00:01

A farmer wants to fence in an area of 1.5 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. How can he do this so as to minimize the cost of the fence?

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Answers (1)
  1. 6 January, 01:59
    0
    If the rectangular field has notional sides

    x

    and

    y

    , then it has area:

    A

    (

    x

    )

    =

    x

    y

    [

    =

    6



    10

    6

    sq ft

    ]

    The length of fencing required, if

    x

    is the letter that was arbitrarily assigned to the side to which the dividing fence runs parallel, is:

    L

    (

    x

    )

    =

    3

    x

    +

    2

    y

    It matters not that the farmer wishes to divide the area into 2 exact smaller areas.

    Assuming the cost of the fencing is proportional to the length of fencing required, then:

    C

    (

    x

    )

    =

    α

    L

    (

    x

    )

    To optimise cost, using the Lagrange Multiplier

    λ

    , with the area constraint:



    C

    (

    x

    )

    =

    λ



    A



    L

    (

    x

    )

    =

    μ



    A



    μ

    =

    3

    y

    =

    2

    x



    x

    =

    2

    3

    y



    x

    y

    =

    {

    2

    3

    y

    2

    6



    10

    6

    sq ft



    {

    y

    =

    3



    10

    3

    ft

    x

    =

    2



    10

    3

    ft

    So the farmer minimises the cost by fencing-off in the ratio 2:3, either-way
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