The heat of vaporization of water is 40.66 kj/mol. how much heat is absorbed when 2.46 g of water boils at atmospheric pressure?

Question

Chemistry

Macie

2 July, 06:46

The heat of vaporization of water is 40.66 kj/mol. how much heat is absorbed when 2.46 g of water boils at atmospheric pressure?

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Conor Tran · Answer 1

Change mass to moles. There are 18 grams in one mole of water.

2.45g / 18g =.14 moles of water

The heat absorbed is 40.66 kJ for each mol so

40.66 x. 14 = 5.5 kJ