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7 June, 08:38

A sample of fluorine gas exerts a pressure of 900 mmHg. When the pressure is changed to 1140 mmHg, the volume is 250 mL. What was the original volume?

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  1. 7 June, 12:05
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    Let's use Boyle's Law here. P1*V1 = P2*V2

    Given: (assuming that there are decimals at the end for Sig Figs)

    P1 = 900. mmHg

    P2 = 1140. mmHg

    V1 = ?

    V2 = 250. mL

    900. mmHg * ? = 1140. mmHg * 250. mL

    ? = 1.27*250. mL

    ? = 318. mL

    Therefore, the original volume is 318mL.
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