An electronic circuit element consists of 23 mg of silicon. An electric current through the circuit adds heat at a rate of 7.4 x 10-3 J/s. At what rate does the temperature of the circuit element increase? Assume that heat does not transfer from the circuit element to the environment. The specific heat capacity of silicon is.

Given that all the heat is absorbed by the silicon element, the calculation is:

Heat = m * specific heat * ΔT

Heat rate = heat / time = m * specif heat * ΔT / time

Where ΔT / time = temperature change rate, which is what you want to calculate

=> ΔT / time = heat rate / (m*specific heat)

You have:

heat rate = 7.4 * 10 ^-3 J/s

m = 23 mg = 23 * 10^ - 3 g

Specific heat = 0.7 J / (g * °C), taken from internet because you forgo to include the information.

=> ΔT / t = [7.4 * 10^ - 3 J/s ] / [ 23 * 10^ - 3 g * 0.7 J / (g*°C) ]

=> ΔT / t = 0.46 °C / s

Answer: 0.46°C / s