If you dissolve 8.50 g of ca (no3) 2 in 755 ml of distilled water what is the concentration in molarity of the calcium nitrate solution

Molarity is defined as the number of moles of solute in 1 L of solution

the mass of Ca (NO₃) ₂ present - 8.50 g

therefore number of moles of Ca (NO₃) ₂ - 8.50 g / 164 g/mol = 0.0518 mol

the volume of solution prepared is 755 mL

therefore if there are 0.0518 mol in 755 mL

then in 1000 mL the number of moles - 0.0518 mol / 0.755 L

molarity is therefore - 0.0686 M