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19 July, 12:39

An old sample of concentrated sulfuric acid to be used in the laboratory is approximately 98.1 percent h2so4 by mass. calculate the molality and molarity of the acid solution. the density of the solution is 1.83 g/ml.

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  1. 19 July, 15:20
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    Basis: 100 mL solution

    From the given density, we calculate for the mass of the solution.

    density = mass / volume

    mass = density x volume

    mass = (1.83 g/mL) x (100 mL) = 183 grams

    Then, we calculate for the mass H2SO4 given the percentage.

    mass of H2SO4 = (183 grams) x (0.981) = 179.523 grams

    Calculate for the number of moles of H2SO4,

    moles H2SO4 = (179.523 grams) / (98.079 g/mol)

    moles H2SO4 = 1.83 moles

    Molarity:

    M = moles H2SO4 / volume solution (in L)

    = 1.83 moles / (0.1L) = 18.3 M

    Molality:

    m = moles of H2SO4 / kg of solvent

    = 1.83 moles / (183 g) (1-0.983) (1 kg / 1000 g) = 588.24 m
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