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31 October, 15:07

For each solution below calculate the millimoles of solute.

a. 1.90 l of 0.00657 m nacn

b. 871 ml of a solution containing 8.49 ppm caco3

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Answers (1)
  1. 31 October, 17:56
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    A

    (1.62 L) x (0.00332 mol/L NaCN) = 0.00538 mol = 5.38 mmol NaCN

    B

    Supposing the solvent to be water, and supposing the density of the solution is near that of pure water:

    (675 g) x (5.23 x 10^-6) / (100.0875 g CaCO3/mol) = 3.53 * 10^-5 mol = 0.0353 mmol CaCO3.
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