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26 July, 04:36

Write a correct and complete nuclear equation for the alpha decay of a parent atom having 102 protons and 167 neutrons useing the symbols for the elements actually involved in the process?

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  1. 26 July, 04:55
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    Alpha partical is a He nucleus. When decaying alpha particle mass is reduced by 4 and atomic number is reduced by 2.

    The actual element which has 102 protons is No (Nobelium).

    Since it has 167 neutrons, the mass = protons + neutrons = 102 + 167 = 269

    after an alpha decay, the new element formed has 100 protons which is Fm (Fermium)

    the alpha decaying equation is,

    ₁₀₂²⁶⁹No → ₁₀₀²⁶⁵Fm + ₂⁴α + heat

    the total mass and the atomic number (numbe rof protons) must be equal in both sides.
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