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25 February, 16:16

What is the molarity of a hydrochloric acid solution prepared by diluting 200.0 ml of 0.500m hcl to a total volume of 1.00 l?

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  1. 25 February, 16:44
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    The molarity of HCl prepared by diluting 200.0 ml of 0.5 M HCl to a total volume of 1.00 L is calculated using the following formula

    M1V1=M2V2

    M1 = 200 ml

    V1 = 0.5 M

    M2=?

    V2 = 1.00 L = 1x 1000 = 1000ml

    M2 is therefore = M1V1/V2

    that is 0.5M x 200 ml/1000 Ml = 0.1 M
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