What is the molarity of a hydrochloric acid solution prepared by diluting 200.0 ml of 0.500m hcl to a total volume of 1.00 l?

The molarity of HCl prepared by diluting 200.0 ml of 0.5 M HCl to a total volume of 1.00 L is calculated using the following formula

M1V1=M2V2

M1 = 200 ml

V1 = 0.5 M

M2=?

V2 = 1.00 L = 1x 1000 = 1000ml

M2 is therefore = M1V1/V2

that is 0.5M x 200 ml/1000 Ml = 0.1 M