In the reaction HCl + NaOH → NaCl (aq) + H2O, if 45.0 milliliters of a 2.0 M HCl react in an excess of NaOH, how many grams of H2O will be produced?

1) HCl + NaOH - > NaCl + H2O

2) 1 mol HCl : 1 mol NaOH: 1 mol NaCl : 1 mol H2O

3) 45.0 ml of 2.0 M HCl = > M = n / V = > n = M*V = 2.0 M * 0.0450 l = 0.090 moles

4) 0.090 moles of HCl = > 0.090 moles of water

molar mass of water = 18.0 g/mol

mass of H2O = moles * molar mass = 0.090 mol * 18.0 g/mol = 1.62 g

Answer: 1.62 g