The decomposition of hi has a rate constant of 1.80 * 10-3 m-1s-1. how much hi remains after 8.50 min if the initial concentration of hi is 4.78 m?

By use second order integrated integrated law

1 / (A) t = Kt + 1 / (A) o

k = constant

t = time in second = 8.50 x60 = 510 sec

(A) o = initial concentration

(A) t = final concentration

1 / (A) t = (1.80 x10^-3) (510) + 1 / 4.78

1 (A) t = 1.127 multiply both side by (A) t

1=1.127 (A) t divide both side by 1.127

(A) t = 0.887 M