Calculate [h+] and [oh-] for a neutral solution at this temperature. express your answers using two significant figures. enter your answers separated by a comma.

When we have Kw = 1.2x10^-15

and according to Kw formula:

Kw = [OH-] [H+]

by substitution:

1.2x10^-15 = [OH-][H+]

when the solution is neutral that means:

[OH-] = [H+]

∴1.2X10^-15 = X^2

∴X = 3.46 x 10^-8

∴[OH-] = [H+] = 3.46x10^-8