A compound is found to contain 7.962 % silicon, 20.10 % chlorine, and 71.94 % iodine by mass. to answer the question, enter the elements in the order presented above. question 1: the empirical formula for this compound is

Empirical formula is calculated as follows

calculate the moles of each element, that is % composition / molar mass

molar masses (Si = 28.09g/mol, Cl = 35.5 g/mol, I=126.9 g/mol)

moles of silicon = 7.962/28.09g/mol = 0.283 moles

moles of chlorine = 20.10 / 35.5g/mol = 0.566 moles

moles of iodine = 71.94 / 126.9 g/mol = 0.567 moles

divide each mole with smallest mole (0.283)

that is silicon = 0.283/0.283 = 1 mole

chlorine = 0.566/0.283 = 2 mole

Iodine = o. 567/0.283 = 2 moles

empirical formula is therefore = SiCl2I2