14KMnO4 + 4C3H5 (OH) 3 7K2CO3 + 7Mn2O3 + 5CO2 + 16H2O How many moles of KMnO4 are consumed to form 0.886 moles of carbon dioxide?

The balanced equation is given as;

14KMnO ₄ + 4C ₃ H ₅ (OH) ₃ → 7K ₂ CO ₃ + 7Mn ₂ O ₃ + 5CO ₂ + 16H ₂ O

14 : 5

The formed moles of CO ₂ = 0.886 mol

The stoichiometric ratio between CO₂ and KMnO₄ is 5 : 14

Hence,

moles of CO₂ / moles of KMnO₄ = 5 / 14

0.886 mol / moles of KMnO₄ = 5 / 14

moles of KMnO₄ = 0.886 mol x 14 / 5

moles of KMnO₄ = 2.4808 mol

hence, consumed KMnO₄ moles = 2.4808 mol