Ask Question
11 August, 07:19

Determine the number of ch2cl2 molecules in 25.0 g ch2cl2. determine the number of ch2cl2 molecules in 25.0 g ch2cl2.

+4
Answers (1)
  1. 11 August, 09:38
    0
    Answer is: there is 1,77·10²³ molecules of CH₂Cl₂.

    m (CH₂Cl₂) = 25 g.

    n (CH₂Cl₂) = m (CH₂Cl₂) : M (CH₂Cl₂).

    n (CH₂Cl₂) = 25 g : 85 g/mol.

    n (CH₂Cl₂) = 0,294 mol.

    N (CH₂Cl₂) = n (CH₂Cl₂) · Na.

    N (CH₂Cl₂) = 0,294 mol · 6,023 1/mol.

    N (CH₂Cl₂) = 1,77·10²³.

    n - amount of substance.

    Na - Avogadro number.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Determine the number of ch2cl2 molecules in 25.0 g ch2cl2. determine the number of ch2cl2 molecules in 25.0 g ch2cl2. ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers