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11 December, 19:16

How would you prepare 1 liter of. 030 m copper 2 sulfate pentahydrate?

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  1. 11 December, 22:41
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    Answer is: dissolve 74,9 grams CuSO₄·5H₂O in one liter volumetric flask.

    V (CuSO₄·5H₂O) = 1 L.

    c (CuSO₄·5H₂O) = 0,30 mol/L.

    n (CuSO₄·5H₂O) = V (CuSO₄·5H₂O) · c (CuSO₄·5H₂O).

    n (CuSO₄·5H₂O) = 1 L · 0,3 mol/L.

    n (CuSO₄·5H₂O) = 0,3 mol.

    m (CuSO₄·5H₂O) = n (CuSO₄·5H₂O) · M (CuSO₄·5H₂O).

    m (CuSO₄·5H₂O) = 0,3 mol · 249,7 g/mol.

    m (CuSO₄·5H₂O) = 74,9 g.
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