How many total atoms are in 0.530 g of P2O5/12131141/dc2696ff? utm_source=registration

In order to calculate the number of atoms present in 0.53 grams of P₂O₅, first calculate the number of moles for given mass.

As, Moles is given as,

Moles = Mass / M. mass

Moles = 0.53 g : 283.88 g. mol⁻¹

Moles = 0.00186 moles

Now calculate the number of Molecules present in calculated moles of P₂O₅.

As,

1 Mole of P₂O₅ contains = 6.022 * 10²³ Molecules

So,

0.00186 Moles of P₂O₅ contain = X Molecules

Solving for X,

X = (0.00186 mol * 6.022 * 10²³ Molecules) : 1 mol

X = 1.12 * 10²¹ Molecules

Also, in P₂O₅ there are 7 atoms, in 1.12 * 10²¹ Molecules there will be ...

= 1.12 * 10²¹ * 7

= 7.84 * 10²¹ Atoms

Result:

7.84 * 10²¹ Atoms are present in 0.53 grams of P₂O₅.