Consider the reaction zn + no - 3 → nh3 + zn (oh) 2 - 4 carried out in an aqueous basic solution. when the equation is properly balanced, what is the total charge on the product side of the equation?

Question

Chemistry

Jordin Marsh

19 May, 01:07

Consider the reaction zn + no - 3 → nh3 + zn (oh) 2 - 4 carried out in an aqueous basic solution. when the equation is properly balanced, what is the total charge on the product side of the equation?

+1

Answers (1)

Know the Answer?

Hassan Mcgee · Answer 1

Balancing the reaction is done to obey the law of nature, particularly, the Law of Definite Proportions. The concept is, the amount of the same element before and after the reaction must be the same. This is actually a redox reaction.

Oxidation half-reaction: Zn + 4 OH⁻ → Zn (OH) ₄²⁻ + 2 e-

Reduction half-reaction: NO₃⁻ + 6 H₂O + 8 e-→ NH₃ + 9 OH⁻

Adding both reaction, we get the overall complete balanced equation:

4Zn + NO ₃⁻ + 6 H₂O + 7 OH⁻ → 4 Zn (OH) ₄²⁻ + NH₃

Thus, the charge in the product side is 4*-2 = - 8.