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17 September, 00:53

Consider the exothermic reaction 4nh3 (g) + 5o2 (g) →4no (g) + 6h2o (g) calculate the standard heat of reaction, or δh∘rxn, for this reaction using the given data. also consider that the standard enthalpy of the formation of elements in their pure form is considered to be zero.

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  1. 17 September, 03:22
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    The first thing you need to know about this problem is that delta total = delta Hf products - delta Hf reactants.

    Delta total = (4*NO + 6*H2O) - (5*O2 + 4*NH3)

    Delta total = [ (4*91.3 kJ/mol) + (6*-241.8 kJ/mol.) - (5*0 kJ/mol.) + (4*-45.9 kJ/mol.)

    Products = 4 * (365.2) + (-1450.8) = - 1085.6 kJ

    Reactants=4 * (-45.9) + 5 * (0) = - 183.6 kJ

    Delta Rxn = (-1085.6 kJ) - (-183.6 kJ) = - 902.0 kJ
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