A 25.0 ml sample of 0.105 m hcl was titrated with 31.5 ml of naoh. what is the concentration of the naoh?

The balanced equation for the above reaction is

NaOH + HCl - - - > NaCl + H₂O

stoichiometry of NaOH to HCk is 11:

number of HCl moles reacted - 0.105 mol/L x 0.0250 L = 0.00263 mol

according to molar ratio, number of HCl moles = number of NaOH moles

therefore number of NaOH moles - 0.00263 mol

number of moles in 31.5 mL - 0.00263 mol

therefore number of NaOH moles in 1000 mL = 0.00263 / 31,5 mL x 1000 mL

molarity of NaOH - 0.0835 M