Ask Question
21 July, 08:42

Calculate the percent composition by mass of oxygen in litharge (gram formula mss=223.2 grams per mole)

+1
Answers (2)
  1. 21 July, 10:47
    0
    The % composition by mass of oxygen in litharge (grams formula mass=223.2 g/mol) is calculated as below

    % composition is percentage by mass of each element in a compound

    which is calculated as follows

    %composition = molar mass of element/molar mass of compound x100

    The molar mass of oxygen = 16 g/mol

    therefore the % composition = 16 g/mol / 223.2 g / mol x100 = 7.17 % of oxygen
  2. 21 July, 11:14
    0
    Litharge is a yellow oxide of lead with a formula of PbO, which is formed by heating lead metal in air.

    The mass of one mole of PbO is 223.2 grams

    1 mole of PbO contains 16 g of oxygen

    Therefore; the percentage of oxygen will be;

    (16/223.2) * 100 = 7.168 %
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Calculate the percent composition by mass of oxygen in litharge (gram formula mss=223.2 grams per mole) ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers