You will need to prepare about 6 g of the copper ammine product. estimate how much cuso4•5h2o you should start with to prepare approximately 6 g of the copper ammine complex.

First we have to write balanced chemical equation:

CuSO₄.5H₂O + 4 NH₃ → [Cu (NH₃) ₄]SO₄. H₂O + 4 H₂O

then calculate the molar mass of both CuSO₄.5H₂O and [Cu (NH₃) ₄]SO₄. H₂O

MM CuSO₄.5H₂O = 249.612 g/mole

MM [Cu (NH₃) ₄]SO₄. H₂O = 245.612 g/mole

from equation we see that:

1 mole CuSO₄.5H₂O - - - gives - - - > 1 mole [Cu (NH₃) ₄]SO₄. H₂O

249.612 g - - - gives - - - > 245.612 g

? grams - - - gives - - - > 6 g complex

By cross multiplication we get that:

mass of CuSO₄.5H₂O required = 6.1 g