Estimate the molar mass of a gas that effuses at 1.80 times the effusion rate of carbon dioxide. answer in units of g/mol.

From Grahams Law the rates of effusion of two gases are inversely proportional to the square roots of their molar masses at the same temperature and pressure.

Therefore; R1/R2 = √mm2/√mm1

The molecular mass of Carbon dioxide is 44 g

Hence; 1.8 = √ (44/x

3.24 = 44/x

x = 44/3.24

= 13.58

Therefore, the molar mass of the other gas is 13.58 g/mol