What ph must the solution have to yield a solution in which the concentration of x + is 3.50*10-3 m? the pka of acetic acid is 4.76. express your answer numerically?

When Ksp = 9.4x10^-6 (given missing in your question)

and Ksp = [X+][C2H3O2-]

so by substitution:

9.4x10^-6 = 3.5x10^-3 * [C2H3O2-]

∴ [C2H3O2-] = 0.0027

then we need to get Ka we can get it from this formula:

Pka = - ㏒Ka

4.76 = - ㏒Ka

∴Ka = 1.7x10^-5

Ka = [H+][C2H3O2-] / [HC2H3O2]

so by substitution:

1.7x10^-5 = [H+]*0.0027 / 1

∴[H+] = 0.0063 m

So finally we can get PH from this formula:

PH = - ㏒[H+]

= - ㏒ 0.0063

∴ PH = 2.2