Determine the root-mean square speed of CO2 molecules that have an average kinetic energy of 4.2 x10-21 J per molecule.

Determine the root-mean-square sped of CO2 molecules that have an average Kinetic Energy of 4.21x10^-21 J per molecule. Write your answer to 3 sig figs.

E = 1/2 m v^2

If you substitute into this formula, you will get out the root-mean-square speed.

If energy is Joules, the mass should be in kg, and the speed will be in m/s.

1 mol of CO2 is 44.0 g, or 4.40 x 10^1 g or 4.40 x 10^-2 kg.

If you divide this by Avagadro's constant, you will get the average mass of a CO2 molecule.

4.40 x 10^-2 kg / 6.02 x 10^23 = 7.31 x 10^-26 kg

So, if E = 1/2 mv^2

v^2 = 2E/m = 2 (4.21x10^-21 J) / 7.31 x 10^-26 kg = 115184.68

Take the square root of that, and you get the answer 339 m/s.