How many moles of ammonium nitrate are necessary to form 0.692 moles water?

First step is to write the balanced equation as follows:

NH4 NO3 (aq) → N2 O (g) + 2H2 O (l)

where (aq) means aqueous and (l) means liquid

From this equation, we find that 1 mole of NH4NO3 yields 2 moles of H2O, thus the ratio between them is 1/2

Now, to get the number of moles (assume it is given the symbol 'n') of ammonium nitrate to form 0.692 moles of water:

n = 0.692 x (1/2) = 0.346 moles