Calculate the temperature, in k, of 2.20 moles of gas occupying 3.30 l at 3.50 atm.

From idea gas equation that is PV=nRT

T = temperature in kelvin

R=gas cosntant (0.0821atm/k/mol)

P=pressure (3.5atm)

V=volume 3.30L

n=number of moles (2.20mole)

T is therefore = PV/nR

T={ (3.50 x3.30) / (2.20 x 0.0821) }=63.95k