Calculate the free-energy change for the dissolution of 1 mole of nabr and 1 mole of nai at 298 k, given that the values of δh°soln are - 1 and - 7 kj/mol for nabr and nai. the corresponding values of δs°soln are + 57 and + 74 j / (mol·k).

The free energy, which has a symbol of ΔG° at standard conditions has the formula:

ΔG° = n (ΔH° - TΔS°)

For NaBr:

ΔG° = (1 mol) [ (-1 kJ/mol) (1000 J/1 kJ) - (298 K) (57 J/mol·K) ]

ΔG° = - 17,986 J

For NaI:

ΔG° = (1 mol) [ (-7 kJ/mol) (1000 J/1 kJ) - (298 K) (74 J/mol·K) ]

ΔG° = - 29,052 J