How many grams of lithium are needed to produce 45.0 grams of lithium nitride, according to the following process?

6 Li (s) + N2 (g) → 2 Li2N (s)

33.41 g of Li

Solution:

The Balanced Chemical equation is,

6 Li (s) + N₂ (g) → 2 Li₂ N (s)

According to equation,

55.76 g (2 mole) Li ₂N is produced from = 41.4 g (6 mole) Li

So,

45 g of Li₂N will be produced from = X g of Li

Solving for X,

X = (45 g * 41.4 g) : 55.76 g

X = 33.41 g of Li