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7 October, 20:41

How many moles of ions are released when 0.27 mol of cobalt (ii) chloride, cocl2, is dissolved in water?

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  1. 7 October, 23:25
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    CoCl₂ (s) → Co²⁺ (aq) + 2Cl⁻ (aq)

    n (CoCl₂) = 0.27 mol

    n (Co²⁺) = n (CoCl₂)

    n (Cl⁻) = 2n (CoCl₂)

    n=n (Co²⁺) + n (Cl⁻) = 3n (CoCl₂)

    n=3*0.27=0.81 mol
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