When 6 grams of zinc are dropped into excess hydrochloric acid, how many grams of zinc chloride will be produced?

Following reaction is initiated with Zn interacts with HCl;

Zn + 2HCl → ZnCl2 + H2

(1mol = 65.38 g) (1 mol = 136.28g)

Thus, 1 mol of Zn generates 1 mol of ZnCl2

Now, 6 g Zn ≡ 0.09177 mol.

Hence, 0.09177 mol of Zn generates 0.09117 mol of ZnCl2.

And 0.09117 mol of ZnCl2 ≡ 12.506 g

Thus, 6 g of Zn when dropped into excess HCl, it will produce 12.506 g of ZnCl2