A solution of malonic acid, h2c3h2o4, was standardized by titration with 0.1000 m naoh solution. if 21.55 ml of the naoh solution were required to neutralize completely 12.55 ml of the malonic acid solution, what is the molarity of the malonic acid solution?

The balanced chemical reaction between NaOH and malonic acid is as follows;

H₂C₃H₂O₄ + 2NaOH - - > Na₂C₃H₂O₄ + 2H₂O

Stoichiometry of H₂C₃H₂O₄ to NaOH is 1:2

The number of moles of NaOH needed for complete neutralisation

- 0.100 mol/L / 1000mL/L x 21.55 mL

Therefore number of NaOH moles that have reacted = 0.002155 mol

For complete neutralisation, number of malonic acid moles = (number of NaOH moles) / 2

malonic acid moles reacted = 0.002155/2 mol

Number of malonic acid moles in 12.55 mL = 0.002155/2 mol

Therefore in 1000 mL volume = (0.002155/2 mol) / 12.55 mL x 1000 mL

Molarity of malonic acid = 0.086 mol/L