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23 August, 12:42

Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. Given the equation: Cu + 2AgNO3 - > Cu (NO3) 2 + 2Ag Avogadro's number: 6.02 x 1023

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  1. 23 August, 15:09
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    1) Chemical equation

    Cu + 2AgNO3 - - - > Cu (NO3) 2 + 2Ag

    2) molar ratios

    1 mol Cu: 2 moles AgNO3 : 1 mol Cu (NO3) 2 : 2 mol Ag

    3) Convert 12. 83 * 10^23 atoms of Cu in moles

    12.83 * 10 ^ 23 atoms / (6.02 * 10^23 atoms / mol) = 2.131 mol Cu

    4) Use the proportions

    2.131 mol Cu * 2 mol Ag / 1 mol Cu = 4.262 mol Ag

    5) Use the atomic mass of silver to convert 4.262 mol in grams

    mass = number of moles * atomic mass = 4.262 mol * 107.9 g / mol = 459.9 grams

    Answer: 459.9 g
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