What is the true, molecular formula of a compound with the empirical formula C13H19O2 and molar mass of 414.64g?

Question

Chemistry

Cristian Leach

9 June, 00:10

What is the true, molecular formula of a compound with the empirical formula C13H19O2 and molar mass of 414.64g?

+5

Answers (1)

Know the Answer?

Amy Thomas · Answer 1

C13H19O2 = (12 * 13) + (1 * 19) + (16 * 2) = 156 + 19 + 32 = 207.

The formula is n = molar mass of molecular formular / molar mass of empirical formular. MM of molecular formula = 414.7 and of empirical formula = 207

So n = 414.7 / 207 = 2.

So the true molecular formula is 2 (C13H19O9) = C26H38O18.