What is the limiting reactant if 0.5 g Al is reacted with 3.5 g CuCl2?

The balanced equation for the above reaction is

2Al + 3CuCl₂ - - > 2AlCl₃ + 3Cu

stoichiometry of Al to CuCl₂ is 2:3

limiting reactant is when the reactant is fully consumed in the reaction therefore amount of product formed depends on amount of limiting reactant present.

number of Al moles - 0.5 g / 27 g/mol = 0.019 mol

number of CuCl₂ moles - 3.5 g / 134.5 g/mol = 0.026 mol

if Al is the limiting reactant

if 2 mol of Al reacts with 3 mol of CuCl₂

then 0.019 mol of Al reacts with - 3/2 x 0.019 = 0.029 mol of CuCl₂

but only 0.026 mol of CuCl₂ is present

therefore CuCl₂ is the limiting reactant

and 0.026 mol of CuCl₂ reacts with - 0.026/3 x 2 = 0.017 mol of Al is required

but 0.019 mol of Al is present

therefore CuCl₂ is the limiting reactant and Al is in excess