The following table lists molar concentrations of seven major ions in seawater. Using a density of 1.022 g/mL for seawater, convert the concentrations for the two ions in the question below into molality. Ions g/kg mM Na + 10.781 480.57 K + 0.399 10.46 Mg2 + 1.284 54.14 Ca2 + 0.4119 10.53 Cl - 19.353 559.40 SO42 - 2.712 28.93 HCO3 - 0.126 2.11 Total 35.067 n/a

magnesium ion = m?

sulfate ion = m?

Question

Chemistry

Natalie Krause

18 April, 06:19

The following table lists molar concentrations of seven major ions in seawater. Using a density of 1.022 g/mL for seawater, convert the concentrations for the two ions in the question below into molality. Ions g/kg mM Na + 10.781 480.57 K + 0.399 10.46 Mg2 + 1.284 54.14 Ca2 + 0.4119 10.53 Cl - 19.353 559.40 SO42 - 2.712 28.93 HCO3 - 0.126 2.11 Total 35.067 n/a

magnesium ion = m?

sulfate ion = m?

+2

Answers (1)

Know the Answer?

Kyle Guerra · Answer 1

d (sea water) = 1,022 g/mL.

V (sea water) = 1 L = 1000 mL.

m (sea water) = d (sea water) V (sea water).

m (sea water) = 1,022 g/mL · 1000 mL.

m (sea water) = 1022 g = 1,022 kg.

m (solvent) = m (sea water) - m (total mass of ions).

m (solvent) = 1022 g - 35,067 g.

m (solvent) = 986,93 g = 0,98693 kg.

c (magnesium ion) = 0,054 mol/L.

b (magnesium ion) = 0,054 mol : 0,98693 kg.

b (magnesium ion) = 0,0548 mol/kg = 0,0548m. b (sulfate ion) = 0,02893 mol : 0,98693 kg. b (sulfate ion) = 0,0293 mol/kg = 0,0293m.