Ask Question
15 July, 11:19

An orange emission line is observed at 656.3 nm in the hydrogen emission spectrum. Determine the initial energy level of the electron.

+3
Answers (1)
  1. 15 July, 12:25
    0
    The energy of a wave is calculated by E = hf where f is the frequency and h is the Planck's constant (6.626 * 10^-34 J/s).

    The formula may be written as E = hc/λ where c is the speed of light 3*10^8 m/s and λ is the wavelength.

    Thus energy = (6.626 * 10^-34) * (3 * 10^8) / (656.3 nm)

    = 3.0267 * 10^ - 19 J

    Therefore, the initial energy level of an electron is 3.0267 * 10^-19 joules.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “An orange emission line is observed at 656.3 nm in the hydrogen emission spectrum. Determine the initial energy level of the electron. ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers