how many grams of solute are needed to make 2.50 liters of a 0.100 m soultion of kcl?

Molarity = number of mole solute/volume (L) solution.

volume (L) solution = 2.50 L

Molarity = 0.100 M KCl

0.100 M KCl = number of mole solute/2.50 L solution

number of mole solute (KCl) = 0.100 M KCl*2.50 L = 0.100*2.50 (mol/L) * L =

=0.250 mol KCl

mass (solute) KCl = Molar mass KCl * number of mole solute (KCl)

Molar mass KCl = 39.1+35.5 = 74.6 g/mol

0.250 mol KCl * 74.6 g/mol KCl = 18.7 g KCl