Determine the number of moles of a gas which occupies 39.0mL at 27°C if the pressure is 107 kPa.

3.14 x 10-3 mol

5.52 x 10-3 mol

2.45 x 10-3 mol

1.67 x 10-3 mol

We can use the ideal gas law equation to solve for the number of moles present

PV = nRT

P - pressure - 107 kPa

V - 39.0 x 10⁻⁶ m³

n - number of moles

R - 8.314 Jmol⁻¹K⁻¹

T - temperature in K - 27 °C + 273 = 300 K

Substituting these values into the equation

107 000 Pa x 39.0 x 10⁻⁶ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 300 K

n = 1.67 x 10⁻³ mol