Ask Question
3 May, 23:56

An aqueous solution of glycerol, c3h8o3, is 48.0% glycerol by mass and has a density of 1.120 g ml-1. calculate the molality of the glycerol solution.

+2
Answers (1)
  1. 4 May, 00:11
    0
    Answer is: the molality of the glycerol solution is 10.03 m.

    V (solution) = 100 mL.

    m (solution) = V (solution) · d (solution).

    m (solution) = 100 mL ·1.120 g/mL.

    m (solution) = 112 g.

    m (glycerol) = ω (glycerol) · m (solution).

    m (glycerol) = 0.48 · 112 g.

    m (glycerol) = 53.76 g.

    m (water) = 112 g - 53.76 g.

    m (water) = 58.24 g : 1000 g/kg = 0.05824 kg.

    n (C₃H₈O₃) = m (C₃H₈O₃) : M (C₃H₈O₃).

    n (C₃H₈O₃) = 53.76 g : 92 g/mol.

    n (C₃H₈O₃) = 0.584 mol.

    b (C₃H₈O₃) = n (C₃H₈O₃) : m (H₂O).

    b (C₃H₈O₃) = 0.584 mol : 0.05824 kg.

    m (C₃H₈O₃) = 10.027 mol/kg.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “An aqueous solution of glycerol, c3h8o3, is 48.0% glycerol by mass and has a density of 1.120 g ml-1. calculate the molality of the ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers