How many moles of libr are contained in 347 g of water in a 0.175 m libr solution?

Molarity = number of moles of solute/Kg of solvent

Molarity is given in the problem as 0.175 m

Mass of solvent = 347 gm = 0.347 Kg

Therefore,

0.175 = number of moles of LiBr / 0.347

number of moles of LiBr = 0.175 x 0.347 = 0.060725 moles