Ask Question
18 May, 21:21

How many moles of libr are contained in 347 g of water in a 0.175 m libr solution?

+4
Answers (1)
  1. 19 May, 00:32
    0
    Molarity = number of moles of solute/Kg of solvent

    Molarity is given in the problem as 0.175 m

    Mass of solvent = 347 gm = 0.347 Kg

    Therefore,

    0.175 = number of moles of LiBr / 0.347

    number of moles of LiBr = 0.175 x 0.347 = 0.060725 moles
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “How many moles of libr are contained in 347 g of water in a 0.175 m libr solution? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers