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29 June, 17:33

How many moles of nacl are required to prepare 0.80 l of 6.4 m nacl? 0.13 mol nacl 5.1 mol nacl 7.2 mol nacl 8.0 mol nacl?

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  1. 29 June, 18:18
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    NaCl = n/V

    6.4M = n/0.80L

    n = 5.12mol
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