A chemist determines by measurements that 0.030 moles of nitrogen gas participate in a chemical reaction. calculate the mass of nitrogen gas that participates.

Remember that:

number of moles = mass/molar mass

First, we get the molar mass of the nitrogen gas molecule:

It is known the the nitrogen gas is composed of two nitrogen atoms, each with molar mass 14 gm (from the periodic table)

Therefore, molar mass of nitrogen gas = 14 x 2 = 28 gm

Second we calculate the mass of the precipitate:

we have number of moles = 0.03 moles (given)

and molar mass = 28 gm (calculated)

Using the equation mentioned before,

mass = number of moles x molar mass = 0.03 x 28 = 0.84 gm